0=3x^2-14x+15

Solution for 0=3x^2-14x+15 equation:

0=3x^2-14x+15

We move all terms to the left:

0-(3x^2-14x+15)=0

We add all the numbers together, and all the variables

-(3x^2-14x+15)=0

We get rid of parentheses

-3x^2+14x-15=0

a = -3; b = 14; c = -15;
Δ = b2-4ac
Δ = 142-4·(-3)·(-15)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-4}{2*-3}=\frac{-18}{-6}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+4}{2*-3}=\frac{-10}{-6}
=1+2/3
$